# How to create a 'dictionary' object? ie. list of name/value pairs

**URL:** <https://connect.superhuman.com/t/how-to-create-a-dictionary-object-ie-list-of-name-value-pairs/24939>\
**Category:** Ask the Community\
**Created:** [August 8, 2021, 12:23am UTC](https://connect.superhuman.com/t/how-to-create-a-dictionary-object-ie-list-of-name-value-pairs/24939 "2021-08-08T00:23:55Z")\
**Posts on this page:** 1\
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**Author:** ![Paul\_Danyliuk](https://yyz1.discourse-cdn.com/coda1/user_avatar/connect.superhuman.com/paul_danyliuk/32/27228_2.png) [@Paul\_Danyliuk](https://connect.superhuman.com/u/Paul_Danyliuk)\
**Post date:** [August 8, 2021, 9:33am UTC](https://connect.superhuman.com/t/how-to-create-a-dictionary-object-ie-list-of-name-value-pairs/24939/2 "2021-08-08T09:33:55Z")

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> [@Max\_OBrien](#):
>
> is there an Object() function ala List() i could use?

As a matter of fact, there is an `Object()` formula now 🙂 It’s hidden because it’s added in preparation for a bigger update, but it’s there

 ![image](https://global.discourse-cdn.com/coda1/original/3X/1/e/1e648898d5406591276231de87ccff123ca41c8e.png)

However, there seems no “legal” way to extract a name by value yet. There’s only this `_Deref_Object()`, another hidden formula, but it cannot look into nested object (the parameter path is not really a path but only a top-level key, and you cannot chain multiple \_Deref\_Object()s):

 ![image](https://global.discourse-cdn.com/coda1/original/3X/4/8/481c384859e51ee5b44c05745cc2ade74250f9c3.png)  
 ![image](https://global.discourse-cdn.com/coda1/original/3X/c/7/c737d9abd591c2a48d89ba7b5945608d03929c27.png)

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